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What are the oxidation numbers of : (a) S in H_(2)SO_(4), (b) Mn in MnO_(4)^(-) (c) N in NH_(4)^(+) and (d) Al in A1O_(2)^(-) (e) Mn in MnO_(4)^(-2) |
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Answer» Solution :(a) 2 (Oxidation number of H)+(Oxidation number of S)+ 4(-2)=0 Oxidation number of S=-2+8=+6 (b) (Oxidation number of Mn)+4(-2)=-1 Oxidation number of Mn =-1+8=+7 (c ) (Oxidation number of N) +4(+1)=+1 Oxidation number of N =+1-4=-3 (d) (Oxidation number of AL)+2(-2)=-1 Oxidation number of Al =-1+4=+3. (E) (Oxidation number of Mn) +4(oxidation number of oxygem)=-2 Oxidation number of Mn=-2+8=+6 |
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