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1. |
What are the possible expressions for the dimensions of the cuboids whose volumes are given below : (i) Volume: 3x2 – 12x (ii) Volume: 12ky2 + 8ky – 20k |
Answer» (i) length × breadth × height = Volume of Cuboid = 3x2 – 12x = 3x2 – 12x = 3x(x – 4) = 3 × x × (x – 4) l × b × h ∴ Length = 3 Breadth = x Height = (x – 4) (ii) length × breadth × height = Volume of Cuboid = 12ky2 + 8ky – 20k 12ky2 + 8ky – 20k = 4k(3y2 + 2y – 5) = 4k (3y2 + 5y – 3y – 5) = 4k (y(3y + 5) – 1 (3y + 5)) = 4k × (3y + 5) × (y – 1) l × b × h ∴ Length = 4k Breadth = (3y + 5) Height = (y – 1) |
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