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What are the values of w and DeltaE, when a system absorbs 250Jof heat by expanding from 1 lit to 10 lit against 0.5 atm pressure and at constant temperature. |
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Answer» Solution :`W=-P Delta v =- 0.5 (10 -1) =- 4.5 `lit - atm WOrk DONE, `w =- 4.5 XX 101 J =- 454 .5 J.` `Delta E =q - w = 250 -454.5 =-204 .5 J.` |
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