1.

What conclusion can be obtained on the basis of following electrochemical cell M|M^(+)||X^(-)|X,E_(M^(+)|M)^(o)=0.44V and E_(X|X^(-))^(o)=0.33V.

Answer»

`M^(+)+X^(-) to M+X` is spontaneous REACTION
`M+X to M^(+)+X^(-)` is spontaneous reaction
`E_(cell)=0.11V`
`E_(cell)=-0.11V`.

Solution :`E_(M^(+)|M)^(o)=0.44V`
CATHODE in half-cell: `underset(("Reactant"))(M^(+))+e^(-) to underset(("Product"))(M)`. . . REDUCTION
`therefore E_(M|M^(+))^(o)` (Oxidation POTENTIAL)=-0.44 V
`E_(X|X^(-))^(o)=0.33V`
`X^(-) to X+e^(-)` (Oxidation) and
`M^(+)+e^(-) to M` (Reduction)
`thereforeo X^(-)+M^(+) to X+M` Reaction will occur itself.


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