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What do you mean by the term 'Depression of freezing point'? |
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Answer» Depression of freezing point: According to Raoult's law, when a non-volatile solid is added to the solvent, its vapour pressure decreases and now it would become equal to that of solid solvent at lower temperature thus, the freezing point of the solvent decreases. Let Tf0 be the freezing point of pure solvent and Tf be its freezing point when non-volatile solute is dissolued in it. The decrease in freezing point ATf = T0f - Tf is known as depression in freezing point. Similar to elevation of boiling point, depression of freezing point (ΔT for dilute solution (ideal solution) is directly proportional to the molality m of the solution Thus, ΔTf ∝ m or, ΔTf ∝ kfm The proportionality constant kf, which depends on the nature of the solvent is known as freezing point depression constant or molal depression constant or cryescopic constant. If w2 gram of the solute having molar mass of M2, present in w1 grain of solvent, produces the depression in freezing point ΔTf of the solvent, then molality of the solute is given by m = {(w2/m2)/(w1/100)} Substituting the values of molality in eq., we get ΔTf = {(kf x w2/M2)/(W1/1000)} ΔTf = {(kf x w2/1000)/(M2 x W1)} |
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