What does the negative sign in the expression `E_(Zn^(2+)//Zn)^(@)=-0.76V` mean?

What does the negative sign in the expression `E_(Zn^(2+)//Zn)^(@)=-0.

1.	What does the negative sign in the expression `E_(Zn^(2+)//Zn)^(@)=-0.76V` mean?
Answer» It implies that Zn is more reactive than hydrogen or it is a stronger reducing agent.In a cell containing zinc electrode and standard hydrogen electrode present in two half cells, zinc will be oxidised to `Zn^(2+)` ions while `H^(+)` ions will get reduced to hydrogen.

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What does the negative sign in the expression `E_(Zn^(2+)//Zn)^(@)=-0.76V` mean?

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