1.

What electronic transition in Li^(2+) produces the radiation of the same wave length as the first line in the Lyman series of hydrogen?

Answer»

N = 4 to n = 2
n = 9 to n = 6
n = 9 to n = 3
n = 6 to n = 3

Solution :`bar(upsilon) = Z^2 R [ 1/(n_1^2) - 1/(n_2^2)]` and E = `hc bar(upsilon)`
`""Li^(2+) ""H`
`(3)^2 (1/(n_1^2) - 1/(n_2^2)) = (1)^2 (1/((1)^2) - 1/((2)^2))`
on solving`n_1 =2 , n_2 = 4`


Discussion

No Comment Found