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What force is required to stretch a copper wire Icnr in crossection to double its length7 (Y=1.3xx10^(11)N//m^(2)). |
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Answer» SOLUTION : Stress =F/A. Strain = `(2l-l)/(I)=1` `:.=("Stress")/("strain")="STRES" =1.3xx10^(11)N//m^(2) :. F="stress" xx A=1.3xx10^(11)xx(1)/(10^(4))=1.3xx10^(7)N` |
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