1.

What happen when diborane reacts with Lewis bases?

Answer»

It FORMS boron TRIHYDRIDE `(BH_(3))` due to cleavage.
It undergoes cleavage to give BORANE adduct `BH_(3)L` (Where, L = Lewis base)
It oxidises to give `B_(2) O_(3)`
It does not react with Lewis bases

Solution :`B_(2)H_(6) + underset(("Lewis base"))(2L) to underset("Adduct")(2BH_(3).L)`
or `B_(2)H_(6) + 2NMe_(3) to 2NH_(3). Nme_(3)`


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