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what happens if a solution of rare H2SO4 is allowed to flow through it in the event of an electrical accident? |
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Answer» tion:Electrolysis of dilute sulphuric acid:-At cathode-2H + +2e − ⟶H 2 At anode-4OH − +⟶2H 2 O+2O 2 +4e − OVERALL reaction-H 2 O⟶2H 2 +O 2 ∴ AMOUNT of substance liberated at cathode = 2 moles of H 2 =4gAlso, amount of substance liberated at anode = 1 mole of O 2 =32g∴ Ratio of the amount of substance liberated at the cathode and anode = 4:32=1:8 |
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