1.

What happens when chloroform is treated with heavy water in presence of an alkali ?

Answer»

Solution :Due to greater electronegativity , the three Cl atoms in `CHCl_(3)`, decrease the electron density in C-H bond. In other words, H in `CHCl_(3)` is slightly acidic and THUS can be easily abstracted by a strong base such as `OH^(-)` to form `"CC"l_(3)^(-)` which then reacts with `D_(2)O` to formdeuterochloroform `(CDCl_(3))`,
`H-"CCl"_(3) underset(-H_(2)O)overset(OH^(-))to overset(-): "CC"l_(3)overset(D_(2)O)to CDCl_(3)+ DOH`


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