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What happens when ? (Give balanced equations) (i)Sodium iodate is treated with sodium bisulphite solution. (ii)Chlorine is passed through hot and concentrated NaOH solution. (iii)Chlorine is passed into dilute and cold potassium hydroxide solution. (iv)Chlorine gas is bubbled through a solution of ferrous bromide. (v)Iodine reacts with concentrated `HNO_(3)`. (vi)Chlorine is passed over slaked lime. (vii)Potassium iodide is heated with `MnO_(2)` and concentrated `H_(2)SO_(4)`. (viii)Chlorine reacts with `Na_(2)SO_(3)` solution. (ix)Iodine is added to acidified stannous chloride solution. |
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Answer» Correct Answer - (i)`2NaIO_(3)+5NaHSO_(3)to3 NaHSO_(4)+2Na_(2)SO_(4)+H_(2)O+I_(2)` (ii)`3Cl_(2)+6NaOH("conc")overset("Hot")to5NaCl+NaCIO_(3)+3H_(2)O` (iii)`Cl_(2)+2KOH(aq)toKCl+KClO+H_(2)O` (iv)`2FeBr_(2)+3Cl_(2)to2FeCl_(3)+2Br_(2)` (v)`I_(2)+10HNO_(3)to2HIO_(3)+10NO_(2)+4H_(2)O` (vi)`Ca(OH)_(2)+Cl_(2)toCa(OCI)CI+H_(2)O` (vii)`2KI+MnO_(2)+3H_(2)SO_(4)to2KHSO_(4) + MnSO_(4) + 2H_(2)O + I_(2)` (viii)`SnCl_(2)+2HCl+I_(2) overset("acidified")to SnCl_(4)+2HI` |
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