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    				| 1. | What happens when H_(3)PO_(3) is heated ? | 
| Answer» <P>Solution :The OXIDATION state of P in `H_(3) PO_(3)` is +3. Since this value is intermediate between the highest (+5) and lowest (-3) oxidation STATES of P, therefore, when `H_(3)PO_(3)` is heated, it undergoes disproportionation to FORM `PH_(3) and H_(3)PO_(4)` with oxidation states of -3 and +5 respectively. `UNDERSET("Orthophosphorous acid")(4H_(3)overset(+3)(PO_(3))) overset("Heat") rarr underset("Phosphine")overset(-3)(PH_(3))+underset("Orthophosphoric acid")overset(+5)(H_(3)PO_(4))` | |