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What happens when (i) 2-Nitropropane boiled with HCl (ii). Nitrobenezen electrolytic reduction in strongly acidic medium. (iii). Oxidation of tert- butylamine with KMnO_(4) (iv). Oxidation of acetoneoxime with trifluoreperoxy acetic acid. |
Answer» Solution :(i) 2- Nitropropane boiled with HCl, 2-nitropropane upon hydrolysis with BOILING HCl give a keton (2-propanone) and nitrous oxide.  (ii). Nitrobenzen electrolytic reduction is strongly acidic medium: Electrolytic reduction of nitrobenzene is weakly acidic medium gives aniine but in strongly acidic medium, it gives p-aminophenol obviously through the acid- catalysed rearrangement of the initially FORMED phenylhydroxylamine.  (iii) Oxidation of tert- butylamine with `KMnO_(4)`: In GENERAL, primary amines, in which the -`NH_(2)` group is attached to a tertiary carbon can be oxidised with `KMnO_(4)` to the corresponding nitro compound in excellent yield. Therefore `3^(@)` -butylamine oxidised to give 2-methyl -2-nitropropane. `CH_(3)-underset((3^(@)-"butylamine"))underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-NH_(2)overset(KMnO_(4))(to)CH_(3)-underset((2-"methyl-2-nitropropane"))underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-NO_(2)` (iv) Oxidation of acetoneoxime with trifluoroperoxy acetic acid: Oxidation acetoneoxime with trifluoroperoxy acetic acid gives 2-nitropropane. `CH_(3)-underset(("Acetoneoxime"))underset(CH_(3))underset(|)(C)=N-OHunderset((O))underset(CF_(3)COOH)(to)CH_(3)-underset((2-"nitropropane"))underset(CH_(3))underset(|)(CH)-NO_(2)` |
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