1.

What happens when (i) Chlorobenzene is treated with Cl_(2)//FeCl_(3) (ii) Ethyl chloride is treated with AgNO_(2) (iii) 2-bromopentane is treated with alcoholic KOH ? Write the chemical equations in support of your answer.

Answer»

Solution :(i) Chlorobenzene is treated with `Cl_(2)//FeCl_(3).`

In the presence of an iron catalyst, chlorine reacts rapidly with BENZENE to give chlorobenzene and `HCl, FeCl_(3),` catalyst substitutes a halogen for an H ATOM.
(II) Ethyl chloride is treated with `AgNO_(2)`:
`CH_(3)CH_(2)Cl+AgNO_(2)rarrCH_(3)CH_(2)NO_(2)+AgCl`
(iii) 2-bromopentane is treated with alcoholic KOH
`CH_(3)-overset(Br)overset(|)CH-CH_(2)-CH_(2)-CH_(3)overset(KOH(alc.Delta))rarrCH_(3)-CH=CH-CH_(2)-CH_(3)+HBr`


Discussion

No Comment Found