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What is amount of minimum air required per kg of liquid fuel for complete combustion using carbon, oxygen, hydrogen and sulfur?(a) 1/23 [8/3 C + 8(H – (O/8)) + S](b) 1/100 [8/3 C + 8(H – (O/8)) + S](c) 1/100 [8/3 C + 8(H – (0/8))](d) 1/23 [8/3 C + 8(H – (0/8))]The question was asked in a job interview.My question is taken from Calorific Value of Fuels topic in chapter Steam Power Plant of Energy Engineering

Answer»

Right answer is (a) 1/23 [8/3 C + 8(H – (O/8)) + S]

Explanation: LET C, H, O and S represent percentage by mass of carbon(C), Hydrogen (H2), OXYGEN and sulfur respectively.

The mass of oxygen required for complete combustion of fuel is given by,

= 1/100 [8/3 C + 8H – O + S]

= 1/100 [8/3C + 8(H – (0/8)) + S]

 As air contains 23% of oxygen by mass, minimum air required for burning one kg of liquid fuel completely is given by,

Min. air required = 1/100 [8/3 C + 8(H – (O/8)) + S] 100/23

= 1/23 [8/3 C + 8 (H – (O/8)) + S].


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