Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Rate of rainfall is expressed in _____________(a) Centimeters(b) Millimeters(c) Meters(d) KilometersThe question was asked by my school teacher while I was bunking the class.This interesting question is from Rainfall and its Measurement in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The correct choice is (a) Centimeters

To elaborate: The rate of rainfall is EXPRESSED in centimeters of water during a given period of time. One centimeter rainfall is the QUANTITY of water COLLECTED on a certain AREA due to rainfall which becomes one centimeter in height.

2.

The graph of the cumulative values of water quantity against time is known as __________(a) Flow curve(b) Power curve(c) Mass curve(d) Load curveI had been asked this question during an online interview.This intriguing question originated from Hydrographs topic in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The CORRECT choice is (c) Mass curve

To explain: The graph of the CUMULATIVE values of water quantity against time is known as mass curve. A mass curve of the HYDROGRAPH which expresses the AREA under the hydrograph from one time to another.

3.

In what way are all the precipitations measured?(a) Vertical depth(b) Horizontal area(c) Width of area(d) At slopeI have been asked this question by my college director while I was bunking the class.The query is from Rainfall and its Measurement in chapter Hydro Electric Power Plant of Energy Engineering

Answer»

The CORRECT answer is (a) Vertical depth

To EXPLAIN: All forms of precipitation are MEASURED on the BASIS of vertical depth of water which would accumulate on the level SURFACE if all the precipitation remained where it fell. The rainfall is usually measured with rain gauges.

4.

Study of shape and features of earth surface is called __________(a) Vegetation(b) Geography(c) Anatomy(d) TopographyI have been asked this question at a job interview.Origin of the question is Rainfall and its Measurement in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The correct choice is (d) Topography

Explanation: The study of the shape and features of the surface of the earth is known as topology and it is a very IMPORTANT factor which is affecting the runoff and also the nature of CATCHMENT AREA DEPENDS on it.

5.

What is used to prevent the entry of debris into turbine?(a) Wiper(b) Fore bay(c) Trash rack(d) FilterThis question was addressed to me by my school teacher while I was bunking the class.The above asked question is from Site Selection for Hydro Electric Power Plants topic in division Hydro Electric Power Plant of Energy Engineering

Answer» RIGHT CHOICE is (c) Trash rack

The explanation: Trash rack is USED to PREVENT the entry of debris which might damage the Wicket gate and turbine. It is a wooden or metal structure and is supported by masonry, that prevents WATERBORNE debris from entering into penstock which than connects to turbine.
6.

Determine the capacity of hydro power plant to be used 10 hours peaking plant assuming daily flow in a river to be constant at 20m^3/s. and overall efficiency is 80%?(a) 1.8835 MW(b) 5.5 MW(c) 3.25 MW(d) 1.0 MWThe question was posed to me during an interview for a job.Query is from Hydrographs in portion Hydro Electric Power Plant of Energy Engineering

Answer» CORRECT OPTION is (a) 1.8835 MW

Explanation: CAPACITY of PLANT:

P = wQHno X 10^-3 KW

P = 9810 X 20 X 12 X 0.80 X 10^-6

= 1.8835 MW.
7.

Two successive Iso-hyetes in the basin drawing of catchment area are measured using _______(a) Planimeter(b) Manometer(c) Mass flow meter(d) ChronometerThis question was addressed to me at a job interview.Question is taken from Rainfall and its Measurement topic in chapter Hydro Electric Power Plant of Energy Engineering

Answer»

Right option is (a) PLANIMETER

Easiest explanation: GENERALLY interval of iso-hyete is one cm. after drawing the iso-hyetes; the area between two successive iso-hyetes is MEASURED by using a Planimeter. The rest of the procedure of finding out the MEAN rainfall is SIMILAR to that described in the second method.

8.

The energy input to the hydrological cycle is by ____________(a) Wind(b) Water(c) Sun(d) HeadThis question was posed to me in an interview.This intriguing question originated from Hydrology topic in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The correct option is (c) Sun

To elaborate: The energy input to hydrological cycle is sun. DUE to sun, water evaporates from water bodies. On cooling, the vapors FORM cloud which FALLS down in the form of RAIN, snow, hail etc which is known as precipitation.

9.

Which type of turbines does modern hydro power plant use?(a) Kaplan turbine(b) Francis turbine(c) Pelton wheel(d) Cross flow turbineI got this question in unit test.My question is taken from Classification of Hydro-Plant topic in division Hydro Electric Power Plant of Energy Engineering

Answer»

The correct ANSWER is (b) FRANCIS turbine

Best explanation: Modern power plants use Francis turbine. Francis turbine is a WATER turbine developed by James Francis. It is an INWARD flow reaction turbine that combines radial and axial flow concepts. These are primarily used for electric production.

10.

What is introduced between the dam and power house?(a) Penstock(b) Draft tube(c) Prime mover(d) Surge tankI have been asked this question in a job interview.My question is taken from Site Selection for Hydro Electric Power Plants in division Hydro Electric Power Plant of Energy Engineering

Answer»

Right option is (d) Surge tank

Explanation: Surge tank is introduced between the dam and POWER house nearest to the power house and PREFERABLY on the high ground to reduce the height of tower to provide better regulation of water pressure in the system during variable LOAD CONDITION.

11.

What is the volume of rainfall in day sec-meters if 6.5cm rainfall occurs over an area of 2400 sq.km?(a) 1805.56 day sec meter(b) 1225 day sec meter(c) 895 day sec meter(d) 1555.22 day sec meterI had been asked this question in a national level competition.This interesting question is from Hydrographs in chapter Hydro Electric Power Plant of Energy Engineering

Answer»

Right option is (a) 1805.56 DAY sec meter

To explain I WOULD SAY: TOTAL RAINFALL

12.

Presence of Corrosive gases like H2S and SO2 affect the voltage drop.(a) True(b) FalseThis question was posed to me at a job interview.The query is from Site Selection for Hydro Electric Power Plants in section Hydro Electric Power Plant of Energy Engineering

Answer»

Right ANSWER is (a) True

The explanation is: Presence of Corrosive gases like H2S and SO2 does affect the VOLTAGE drop at brush contacts in generator leading to poor commutation. SILVER contacts of relays get blackened and lead to HIGH contact resistance and failure of RELAY occurs.

13.

Cusec is___________(a) A unit of flow equal to one cubic feet per sec(b) A unit of flow equal to one centimeter cube per sec(c) A unit of flow equal to one meter per sec(d) A unit of flow equal to one cubic foot per secI have been asked this question in unit test.This key question is from Hydrographs topic in section Hydro Electric Power Plant of Energy Engineering

Answer» CORRECT choice is (a) A unit of flow EQUAL to one cubic feet per sec

For explanation I would say: Cusec is a unit of flow ESPECIALLY water which is equal to one cubic feet per sec. And there is also USE of Cumec which is one cubic meter per SECOND. One cubic feet per second is equal to 28.317 liters per second.
14.

What information does the year wise hydrograph gives?(a) Draught(b) Heavy rainfall(c) Rising cold(d) Water scarcityI got this question in an interview for internship.Asked question is from Hydrographs in division Hydro Electric Power Plant of Energy Engineering

Answer»

Right option is (a) Draught

For explanation I would say: The hydrograph can be drawn taking DAY, month or YEAR as time axis. The hydrograph BASED on year wise data GIVES information concerning the lean or draught year. This is very essential for deciding the location and size of hydel POWER plant.

15.

Which gauge gives the permanent record of rainfall?(a) Recording gauge(b) Non-recoding gauge(c) Copper daily gauge(d) Plastic gaugeI got this question in examination.Question is from Rainfall and its Measurement in portion Hydro Electric Power Plant of Energy Engineering

Answer»

Right choice is (a) Recording gauge

Best explanation: These are rain gauges which can give a PERMANENT, automatic rainfall record in the form of a pen mounted on a clock driven chart. From the chart INTENSITY or rate of rainfall in cm per HOUR. The recording is DONE by an attached siphon.

16.

Which type of penstock is used in cold climates?(a) Buried penstock(b) Covered penstock(c) Open penstock(d) Exposed penstockI got this question in examination.My doubt stems from Site Selection for Hydro Electric Power Plants in division Hydro Electric Power Plant of Energy Engineering

Answer»

Correct option is (a) BURIED penstock

Best explanation: Buried penstocks are USED in cold climates where FREEZING is expected. TYPES of penstocks have shorter life period. A buried penstock will not be subjected to the problem of harmonic VIBRATIONS sometimes associated with the traditional penstock.

17.

What is the basic requirement of hydroelectric power station?(a) Reservoir(b) Turbine(c) Power house(d) PenstockThis question was addressed to me in an interview for job.This key question is from Site Selection for Hydro Electric Power Plants in division Hydro Electric Power Plant of Energy Engineering

Answer»

Right choice is (a) Reservoir

The best explanation: The basic requirement of a hydroelectric power station is a reservoir where LARGE quantity of water is STORED during flood season and used during dry season. The reservoir is generally built of constructing dam ACROSS river.

18.

What does ADF stand for in hydrology?(a) Automatic direction finder(b) Average daily flow(c) Average duration flow(d) Annual dry flowI have been asked this question in an interview for job.Origin of the question is Hydrographs in portion Hydro Electric Power Plant of Energy Engineering

Answer» CORRECT choice is (b) Average DAILY FLOW

Best explanation: The daily effluent flow is required to calculate the area of SEPTIC field or the length of trench REQUIRES. It is also referred as the amount of water let out of a reservoir on the daily basis as per the requirement and demand.
19.

Unit hydrograph was explained by Sherman in which year?(a) 1925(b) 1928(c) 1932(d) 1945The question was posed to me in an interview.The query is from Hydrographs in section Hydro Electric Power Plant of Energy Engineering

Answer»

Right choice is (c) 1932

To elaborate: This unit hydrograph PRINCIPLE was EXPRESSED by Sherman in 1932; he introduced the THEORY of unit hydrograph. He POINTED out that all hydrographs have same TIME resulting from rainfalls of the given duration.

20.

What is the primary intention of rain gauging in hydro electric plant?(a) To determine force of storm(b) To determine monthly rainfall(c) To determine annual rainfall(d) To determine monthly and annual rainfallI got this question in exam.The question is from Rainfall and its Measurement in section Hydro Electric Power Plant of Energy Engineering

Answer» RIGHT answer is (d) To determine MONTHLY and annual rainfall

The explanation: The primary INTENTION of the rain gauging in hydroelectric work is to determine the monthly and annual rainfalls over catchment area. When the rain-gauging stations are more than one for a particular basin, calculation of AVERAGE rainfall depending UPON the area of the basin is done.
21.

The intensity of rainfall is given by ______(a) I = R/(T+C)(b) I = R/(T×C)(c) I = (T×C)/R(d) I = (T+R)/CThe question was posed to me in semester exam.Question is taken from Rainfall and its Measurement topic in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The correct choice is (a) I = R/(T+C)

The explanation: The intensity of rainfall is given by,

I = R/(T+C)

Where, I = intensity in inches/hr.

T = Duration of rain storm in hours

R & C = these are constants quoted by different AUTHORITIES for different AREAS of world.

The intensity also DEPENDS on the area selected for the measurement.

22.

Intensity of rainfall is measured by___________(a) Continuously recording gauge(b) Anemometer(c) Hydrometer(d) SeismometerI got this question by my school principal while I was bunking the class.This interesting question is from Rainfall and its Measurement in section Hydro Electric Power Plant of Energy Engineering

Answer»

Correct CHOICE is (a) Continuously recording gauge

Explanation: The INTENSITY of rainfall is expressed as an AMOUNT of precipitation in a stead period. During heavy rainstorm the intensity of rainfall varies widely from minute to minute and can be measured only with a continuously recording gauge.

23.

What are used to store water during peak periods?(a) Storage drums(b) Canals(c) Sews(d) Storage ReservoirsI got this question in an online quiz.The doubt is from Hydrology in portion Hydro Electric Power Plant of Energy Engineering

Answer»

Correct answer is (d) Storage Reservoirs

The best I can EXPLAIN: The capacity of the HYDRAULIC plant is done on the basis of minimum quantity available. Usually storage reservoirs are constructed for such plants in order to STORE the water during peak PERIODS of RUNOFF and supply the same during off peak periods of runoff.

24.

Rainfall is also known as ___________(a) Precipitation(b) Condensation(c) Infiltration(d) Down pourI had been asked this question in an online quiz.I'm obligated to ask this question of Rainfall and its Measurement topic in section Hydro Electric Power Plant of Energy Engineering

Answer»

Right choice is (a) Precipitation

The best explanation: The RAINFALL is ALSO known as precipitation, is a natural PROCESS of atmospheric vapor into water. Atmospheric vapor are nothing but clouds which are contamination of air and water. When the temperature GOES below dew point then precipitation takes PLACE.

25.

Capacity of hydraulic plant is dependent on __________(a) Minimum quantity of water available(b) Vegetation of the selected area(c) Maximum quantity of water available(d) Available headI have been asked this question during an online interview.This interesting question is from Hydrology in portion Hydro Electric Power Plant of Energy Engineering

Answer»

Right answer is (a) Minimum quantity of water AVAILABLE

Easy explanation: As the availability of water depends on natural phenomenon of rain, the MAXIMUM capacity of hydraulic generating plant is USUALLY FIXED on the basis of minimum quantity of water available at selected site.

26.

A lake behind a dam has a capacity of 30000km^2-m approximately. For how many days would this water supply be sufficient to a city of 10^6 populations if daily requirement per person is 500 liters?(a) 60,000 days(b) 950 days(c) 25000 days(d) 8000 daysThis question was addressed to me at a job interview.The question is from Hydrographs in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The CORRECT choice is (a) 60,000 DAYS

The explanation: Per DAY requirement: 500 X 10^3 liter = 500 X 10^3 m^3

Available WATER in the dam = 30000 X 10^6 m^3

No of days water supplied = 30000 X 10^6/500 X 10^3 = 60000 days.

27.

Which type of hydro power plant can be with or without pondage?(a) Mini hydel plants(b) Pump storage power plants(c) Low head plants(d) Run-off river power plantsThis question was posed to me by my college professor while I was bunking the class.This question is from Classification of Hydro-Plant topic in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The correct OPTION is (d) Run-off river POWER plants

To explain I WOULD say: Run-off river power plants can be with or WITHOUT pondage. A runoff river plant without pondage has no control over river flow and uses WATER as it comes. The runoff river plant with pondage may supply base load power.

28.

Determine the power developed, IF given data is H = 150m, ng = 0.91, nt = 0.86 and Q is 9639.8?(a) 74MW(b) 75MW(c) 76MW(d) 78MWThis question was posed to me in final exam.My question is based upon Hydrographs topic in section Hydro Electric Power Plant of Energy Engineering

Answer»

Correct ANSWER is (a) 74MW

Easiest EXPLANATION: Power developed = wQHno X 10^-3 KW

= 9810 X 9639.8 X 0.86 X 0.91 X 10^-6 MW

= 74 MW.

29.

What is DWF?(a) Deep water flow(b) Dry weather flow(c) Drawing web format(d) Dam water floodThe question was asked by my college professor while I was bunking the class.Question is taken from Hydrographs topic in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The correct choice is (b) DRY weather flow

For explanation: Dry weather flow is a WASTE WATER flow in a sewer system during dry WEATHERS with minimum filtration process while entering the ground. Insufficient flow VELOCITIES during DWF can increase retention.

30.

Hydrographs of similar rainfalls will be similar in shape.(a) True(b) FalseThis question was posed to me in quiz.This question is from Hydrographs in portion Hydro Electric Power Plant of Energy Engineering

Answer»

Right OPTION is (a) True

For explanation: Hydrographs of various rainfalls will be similar in shape. The ordinates are proportional to the runoff VOLUMES within a FIXED duration and similar rate and a REAL DISTRIBUTION of rainfall. However, the occurrence of identical rainfall is very rare.

31.

Thiesson method is better result than arithmetic mean method because _________(a) It is shorter time consuming(b) Gives better detail about records(c) It is highly accurate(d) Small procedureI had been asked this question in exam.This interesting question is from Rainfall and its Measurement topic in division Hydro Electric Power Plant of Energy Engineering

Answer»

Correct choice is (c) It is highly accurate

Easy explanation: The mean rainfall of the basinin THIESSON method is given by:

HA = \(\frac{h1A1 + h2A2 + h3A3 + h4A4 + h5A5+ h6A6 + h7A7 + h8A8}{A1+A2+A3+A4+A5+A6+A7+A8}\)

This method gives better result than arithmetic mean method because it is very accurate and each point on a perpendicular bisector of the line joining the two gauging stations will be equidistant from both the stations. If one moves SLIGHTLY this or that SIDE of the bisector, the position will DISTINCTLY fall in the domain of that station of which ones position is now near.

32.

In which of the following season is evaporation loss from free water is large?(a) Winter(b) Spring(c) Autumn(d) SummerThis question was posed to me in final exam.I need to ask this question from Rainfall and its Measurement topic in section Hydro Electric Power Plant of Energy Engineering

Answer»

The correct answer is (d) Summer

The best explanation: During summer, the evaporation loss from free WATER surface is considerably LARGE and this evaporated water finds ROOM in the air mass. The water holding CAPACITY of air in the form of vapor is ALSO considerably large in hot weather.

33.

The shaft power developed by the water passing through the prime mover is given by _______(a) P =\(\frac{mgH}{1000}\) × no^.(b) P =\(\frac{mgH}{10}\) × no^.(c) P =\(\frac{mgH}{100}\) × no^.(d) P =\(\frac{mgH}{n_{o^.}}\) × 1000I got this question in an international level competition.My question is from Hydrology topic in section Hydro Electric Power Plant of Energy Engineering

Answer» RIGHT OPTION is (a) P =\(\frac{mgH}{1000}\) × no^.

To explain I would say: Where, m = Rate of WATER flow in kg/sec.

H = Height of fall in meters.

no = OVERALL efficiency.
34.

A hydel plant is supplied from a reservoir of 5 X 10^6 m^3 capacity at a head of 75m. Determine the number of electrical units produced (KWh) during the year if the load factor is 0.6 and overall efficiency of generation is 72%?(a) 441.45MWh(b) 300.22MWh(c) 235MWh(d) 182MWhI got this question in quiz.My question comes from Hydrographs in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The correct answer is (a) 441.45MWh

The BEST I can EXPLAIN: The power capacity of plant in KW is given as

P = mgH/1000 X n{overall}

= (5 X 106 X 1000 X 9.81 X 75 X 0.72) / (365 X 24 X 3600 X 1000)

= 83.99Kw

Energy produced in KWH = P X Load factor X (365 X 24)

= 83.99 X 0.6 X 365 X 24

= 4441451.44kwh

= 441.45 MWH.

35.

Which plants are used with steam and IC engines?(a) Pumped storage plants(b) Mini hydel plants(c) Low head Hydel plant(d) Run-off river plantsI got this question by my college director while I was bunking the class.My question is from Classification of Hydro-Plant in section Hydro Electric Power Plant of Energy Engineering

Answer»

Correct option is (a) Pumped storage PLANTS

Explanation: Pumped storage plants can be used with hydro, steam and IC engines. The generating pumping unit is at the lower end. During off peak HOURS some of the surplus electric energy generated by the base plant is utilized to pump WATER from TAIL water pond into the head water pond.

36.

What is the theoretical number of unit hydrographs for given basin?(a) 500(b) 2900(c) 36000(d) infiniteThe question was posed to me in an international level competition.My question is from Hydrographs topic in division Hydro Electric Power Plant of Energy Engineering

Answer»

Right OPTION is (d) INFINITE

The explanation is: The number of unit hydrographs for a given basin is theoretically infinite. This is because there may be one unit hydrograph for POSSIBLE duration of RAINFALL and every possible distribution pattern of rainfall in the basin.

37.

The maximum rate of flow through the river is calculated by _________(a) Energy curves of flow(b) Force of flow(c) Pressure of flow(d) Head of flowThe question was asked in semester exam.My query is from Rainfall and its Measurement in section Hydro Electric Power Plant of Energy Engineering

Answer»

Right option is (a) Energy curves of flow

Easiest explanation: The maximum RATE of flow through the river is calculated by energy curves. Flood marks are also used to GET the maximum flow rate. The following curves include DICKENS FORMULA, Inglis formula and ryve’s formula.

38.

Which among the following method is very accurate of rain gauging?(a) Arithmetic mean method(b) Thiesson method(c) Iso-hyetol method(d) Recording typeI had been asked this question in an online interview.This is a very interesting question from Rainfall and its Measurement topic in portion Hydro Electric Power Plant of Energy Engineering

Answer»

Correct option is (b) Thiesson method

For explanation: Thiesson method is very ACCURATE compared to other methods and is generally used when the catchment area lies between 500 to 5000km square. Assume that there are stations in the GIVEN basin names=d as 1, 2, 3, 4, 5, 6, 7, and 8. It is very important to divide the total basin area in such a way that each located station in the basin represents that area in the TRUE.

39.

Vegetation affects the runoff.(a) True(b) FalseI have been asked this question in exam.My question is from Rainfall and its Measurement topic in portion Hydro Electric Power Plant of Energy Engineering

Answer»

Correct answer is (a) True

The explanation is: The transpiration and INTERCEPTION losses depend on the nature and EXTENT of vegetation including CROPS. Vegetation, particularly of forest, has considerable effect upon the runoff. It consumes a PROPORTION of the rainfall, causes interception losses and provides physical OBSTRUCTION for runoff.

40.

The annual rainfall at any given station varies from _________(a) month to month(b) weekly basis(c) year to Year(d) quarterlyI got this question during an online interview.I want to ask this question from Rainfall and its Measurement topic in section Hydro Electric Power Plant of Energy Engineering

Answer»

Correct answer is (c) year to Year

The EXPLANATION is: The annual rainfall at any given station varies irregularly from year to year. The RANGE of this VARIATION marks the RELIABILITY of the rainfall and has great importance in the design of storage reservoirs.

41.

When does vapor turn into form of water or snow?(a) Cooled below Dew point(b) At Frost point(c) When cooled Freezing point(d) When there is rise in HumidityThis question was posed to me in an interview for job.My question is based upon Hydrology topic in division Hydro Electric Power Plant of Energy Engineering

Answer» RIGHT choice is (a) Cooled below Dew point

To EXPLAIN I would say: Water is evaporated from surface of earth and stored in form of clouds. When the vapors in the ATMOSPHERE are cooled below dew point temperature, it falls in the form of water or snow DEPENDING on the ATMOSPHERIC temperature.
42.

On what aspect is precipitation calculated?(a) Based on hydrological aspect(b) Based on climatic conditions(c) Based on the vegetation of the area(d) Based on weather forecastThis question was posed to me by my school principal while I was bunking the class.This intriguing question originated from Hydrology topic in portion Hydro Electric Power Plant of Energy Engineering

Answer»

Correct answer is (a) Based on hydrological aspect

To EXPLAIN I would say: The EVAPORATION of the water from the SURFACES of river and oceans and its precipitation on the earth is known as hydrological cycle. Based on hydrological aspect the distribution of precipitation on the earth SURFACE and BENEATH the earth is calculated.

43.

Which type of valves is preferred for moderate heads?(a) Butterfly valve(b) Tube valve(c) Needle vale(d) Globe valveI got this question by my college professor while I was bunking the class.Origin of the question is Classification of Hydro-Plant in portion Hydro Electric Power Plant of Energy Engineering

Answer»

Right choice is (a) Butterfly valve

To ELABORATE: For moderate HEADS butterfly VALVES are preferred. Gate valves are used to regulate the flow. This valve is used both as intake gate and as turbine valve. It helps INSPECTION without dewatering the penstock line.

44.

The unit hydrographs can be successfully applied to basin areas of what sq km?(a) 15000 sq km(b) 10000 sq km(c) 3000 sq km(d) 25000 sq kmThe question was posed to me by my college professor while I was bunking the class.Question is taken from Hydrographs topic in portion Hydro Electric Power Plant of Energy Engineering

Answer»

Right option is (d) 25000 SQ KM

To explain: The unit hydrographs can be applied successfully to basin areas as large as 25000 sq km. provided distribution patterns are classified into different types and unit hydrographs are developed for each TYPE it is always PREFERABLE to divide the large basin into sub-areas, UTILIZE hydrographs for each sub area independently and combine the resulting hydrographs together.

45.

Which among the following reduces the capacity of reservoir and causes rapid erosion of turbine blades?(a) Contamination of highly corrosive material(b) Sedimentation effect(c) Submerged vegetation(d) Solid contaminationI got this question by my college director while I was bunking the class.Query is from Site Selection for Hydro Electric Power Plants in section Hydro Electric Power Plant of Energy Engineering

Answer»

The correct choice is (b) Sedimentation effect

Easy explanation: SEDIMENTS in the aquatic ECOSYSTEM are analogous to SOIL in the terrestrial ecosystem as they are the SOURCE of substrate nutrients, and micro- and MACRO flora and -fauna that are the basis of support to living aquatic resources.

46.

What is the unit of runoff ________(a) Day-sec meter(b) M^2/s(c) MM/S^2(d) Ns/m^2I got this question by my college director while I was bunking the class.Question is from Hydrology topic in section Hydro Electric Power Plant of Energy Engineering

Answer»
47.

Which plants supply the peak load for the base power plants?(a) Mini hydel plants(b) Pump storage power plants(c) Low head plants(d) Run-off river power plantsI had been asked this question in class test.The query is from Classification of Hydro-Plant topic in section Hydro Electric Power Plant of Energy Engineering

Answer»

Correct CHOICE is (B) Pump storage power PLANTS

The best I can explain: Pumped storage plants supply the peak load for the base power plants and pump all or a PORTION of their own water supply. The PLANT contains a tail water pond and a head water pond connected by a penstock.

48.

Which type of penstocks is less expensive?(a) Buried penstock(b) Covered penstock(c) Open penstock(d) Exposed penstockI had been asked this question in an interview.This is a very interesting question from Site Selection for Hydro Electric Power Plants topic in division Hydro Electric Power Plant of Energy Engineering

Answer»

Correct CHOICE is (d) Exposed penstock

Explanation: Exposed penstocks are less expensive and have a longer life. Their inspection and maintenance is easier. Penstocks are not covered because exposed PIPES are easily accessible. The WATER flow rate is 2, 4, and 7 m/s in LOW, medium and high head power plants respectively.

49.

Determine the capacity of hydro power plant to be used 8 hours peaking plant assuming daily flow in a river to be constant at 65m^3/s. and overall efficiency is 80% and head 12m?(a) 6.1214 MW(b) 5.5 MW(c) 31.25 MW(d) 22.0 MWI got this question in a job interview.This intriguing question originated from Hydrographs topic in division Hydro Electric Power Plant of Energy Engineering

Answer» RIGHT choice is (a) 6.1214 MW

The explanation: CAPACITY of plant:

P = wQHno X 10^-3 KW

P = 9810 X 65 X 12 X 0.80 X 10^-6

= 6.1214MW.
50.

What would be the pondage factor for if hydropower plant is used for 10 hours?(a) P.F = 2.4(b) P.F = 1.2(c) P.F = 20(d) P.F = 0.4166This question was addressed to me in my homework.Question is from Hydrographs topic in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The CORRECT OPTION is (a) P.F = 2.4

Best explanation: Pondage factor = T1/T2 = (TOTAL number of hours in one day)/(Total number of hours PLANT is running)

P.F = 24/10= 2.4.