1.

A hydel plant is supplied from a reservoir of 5 X 10^6 m^3 capacity at a head of 75m. Determine the number of electrical units produced (KWh) during the year if the load factor is 0.6 and overall efficiency of generation is 72%?(a) 441.45MWh(b) 300.22MWh(c) 235MWh(d) 182MWhI got this question in quiz.My question comes from Hydrographs in portion Hydro Electric Power Plant of Energy Engineering

Answer»

The correct answer is (a) 441.45MWh

The BEST I can EXPLAIN: The power capacity of plant in KW is given as

P = mgH/1000 X n{overall}

= (5 X 106 X 1000 X 9.81 X 75 X 0.72) / (365 X 24 X 3600 X 1000)

= 83.99Kw

Energy produced in KWH = P X Load factor X (365 X 24)

= 83.99 X 0.6 X 365 X 24

= 4441451.44kwh

= 441.45 MWH.



Discussion

No Comment Found

Related InterviewSolutions