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The shaft power developed by the water passing through the prime mover is given by _______(a) P =\(\frac{mgH}{1000}\) × no^.(b) P =\(\frac{mgH}{10}\) × no^.(c) P =\(\frac{mgH}{100}\) × no^.(d) P =\(\frac{mgH}{n_{o^.}}\) × 1000I got this question in an international level competition.My question is from Hydrology topic in section Hydro Electric Power Plant of Energy Engineering |
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Answer» RIGHT OPTION is (a) P =\(\frac{mgH}{1000}\) × no^. To explain I would say: Where, m = Rate of WATER flow in kg/sec. H = Height of fall in meters. no = OVERALL efficiency. |
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