1.

What is (are) number (s) of unpaired electron(s) in the square planar [Pt(CN)_4]^(2-) ion ?

Answer»

Zero
1
4
6

Solution :Outer electronic configuration of PT is `5d^(9) 6s^(1)`. Outer electronic configuration of `Pt^(2+)" is "5d^(8)`
As `CN^(-)` is strong FIELD ligand, so paring will take place.
`Pt^(2+)`


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