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What is beats? Give an analytical description of the phenomenon of beats. Show that the beat frequency is equal to the difference of frequencies of the component oscillation. |
Answer»
Let us consider two waves of slightly different frequencies n1 and n2 (n1 ~ n2 < 10) having equal amplitude travelling in a medium in the same direction. At time t = 0, both waves travel in same phase. The equations of the two waves are y1 = a sin ω1t y1 = a sin (2πn1)t …... (1) y2 = a sin ω2t = a sin (2πn2)t …... (2) When the two waves superimpose, the resultant displacement is given by y = y1 + y2 y = a sin (2πn1)t + a sin (2πn2)t …... (3) Therefore y = 2a sin 2π(n1+ n2/2)t cos 2π(n1– n2/2)t …... (4) Substitute A = 2a cos 2π(n1– n2/2)t and n = n1 + n2/2 in equation (4) y = A sin 2πnt This represents a simple harmonic wave of frequency n = n1 + n2/2 and amplitude A which changes with time. (i) The resultant amplitude is maximum (i.e) ± 2a, if cos 2π [n1-n2/2] t = ±1 So, 2π [n1-n2/2] t = ±mπ (Here, m = 0,1,2....) or (n1 – n2)t = m The first maximum is obtained at t1 = 0 The second maximum is obtained at, t2 = 1/n1 – n2 The third maximum at t3 = 2/n1 – n2 and so on. The time interval between two successive maxima is, t2 – t1 = t3 – t2 = 1/n1 – n2 Hence the number of beats produced per second is equal to the reciprocal of the time interval between two successive maxima. |
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