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What Is bond order ? Explain by example. |
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Answer» Solution :Bond order according to Lewis : The bond order is given by the number of bonds (SHARED electron pair) between the two atoms in a molecule. e.g. : Bond order in `H_(2), F_(2), Cl_(2)`, HCl is one. In `O_(2) ` bond order two and in`N_(2) ` three because shared electron pairs between two atoms is respectively 2 and 3. According to MO theory bond order : `(1)/(2) (N_(b) - N_(a)) ` where , `N_(b)`= Total no. of boding `e^(-)` of BMO `N_(a)` = Total no. of anti BONDING `e^(-)` of ABMO Bond order : the difference of electron in MO and ABMO orbitals divided by 2 is called Bond order. e.e. :Bond order in`H_(2) = (1)/(2) (N_(b) - N_(a))` `= (1)/(2)( 2 - 0) = 1 ` = `(1)/(2)(2 - 0) = 1 ` Bond order in `F_(2) , Cl_(2) , Br_(2) =(1)/(2) (N_(b) - N_(a))` = `(1)/(2) (10 - 8) = 1 ` Bond order BO in `O_(2) = (1)/(2) (10 - 6 ) = 2 ` Bond order BO in `N_(2) = (1)/(2) = (10 - 4) = 3` |
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