What is correct for bond order ?

1.	What is correct for bond order ?
Answer» BO = ABMO no. of ELECTRONS - BMO no. of electronsno. of `e^(-)` INNO. of `e^(-)` in BO = ` ("BMO- ABMO")/(2)` no. of `e^(-)`in no. of `e^(-)` in `BO = (" ABMO -BMO")/(2)` BO = BMO - BMO Solution :BO = ` ("BMO- ABMO")/(2)` no. of `e^(-)`in no. of `e^(-)` in

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