1.

What is correct ratio of Ni^(2+) ions to Ni^(3+) ions in Ni_(0.98)O ?

Answer»

`24 : 1 `
`1:4 `
`47 : 3 `
`47 : 2 `

Solution :Let, NUMBER of `N i^(2+)` IONS = X
Number of `N i^(2+)` ions `= (98 - x)`
As COMPOUND is neutral, `3(98 - x) + 2x = 2 xx 100`
`therefore x = 94`
Number of `N i^(2+)` ions = 94
Number of `N i^(2+)` ions = 4
RATIO of `N i^(2+)` ions to `N i^(2+)` ions `= 94 : 4 = 47 : 2 `


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