What is crystal field splitting energy? How does the magnitude of `triangle_(0)` decide the actual configuration of d orbitals in a coordination entity?A. if `Delta_(0) lt P` , the configuration is `t_(2g)^(3) e_(g) ^(1)` = weak field ligand and high spin complexB. If `Delta_(0) gt P` , the configuration is `t_(2 g)^(3) e_(g) ^(1)` = strong field ligand and low spin complexC. if `Delta_(0) gt P` , the configuration is `t_(2g)^(4) e_(g)^0 `= strong field ligand and high spin complexD. if `Delta_(0) = P` , the configuration is `t_(2g)^(4) e _(g)^(0)` = strong field ligand and high spin complex .

What is crystal field splitting energy? How does the magnitude of `tri

1.	What is crystal field splitting energy? How does the magnitude of `triangle_(0)` decide the actual configuration of d orbitals in a coordination entity?A. if `Delta_(0) lt P` , the configuration is `t_(2g)^(3) e_(g) ^(1)` = weak field ligand and high spin complexB. If `Delta_(0) gt P` , the configuration is `t_(2 g)^(3) e_(g) ^(1)` = strong field ligand and low spin complexC. if `Delta_(0) gt P` , the configuration is `t_(2g)^(4) e_(g)^0 `= strong field ligand and high spin complexD. if `Delta_(0) = P` , the configuration is `t_(2g)^(4) e _(g)^(0)` = strong field ligand and high spin complex .
Answer» Correct Answer - A If CFSE `(Delta)_(0) lt P` (Energy required for pairing) , the electrons do not pair up and fourth electron goes to `e_(g)` of higher energy . Hence , high spin complex is formed . Pairing of electrons does not take place in case of weak field ligands .

Discussion

No Comment Found

Related InterviewSolutions

The coordination number of `Ni^(2+)` is 4. `NiCl_(2) + KCN ("excess") rarr A ("cyano comples")` `NiCl_(2) + conc. HCl ("excess") rarr B ("chloro complex")` Predict the magnetic nature of A and B.A. Both are diamagneticB. A is diamagnetic and B is paramagnetic with one unpaired electronC. A is diamagnetic and B is paramagnetic with two unpaired electronsD. Both are paramagnetic
The coordination number of `Ni^(2+)` is 4. `NiCl_(2) + KCN ("excess") rarr A ("cyano comples")` `NiCl_(2) + conc. HCl ("excess") rarr B ("chloro complex")` The hybridisation of A and B areA. `dsp^(2), sp^(3)`B. `sp^(3), sp^(3)`C. `dsp^(2), dsp^(2)`D. `sp^(3)d^(2), d^(2) sp^(3)`
Why are low spin tetrahedral complexes not formed ?A. for tetrahedral complexes , the CFSE is lower than pairing energyB. for tetrahedral complexes , the CFSE is higher than pairing energyC. electrons do not go to `e_(g)` in case of tetrahedral complexesD. tetrahedral complexes are formed by weak field ligands only .
The complex that violates the EAN:A. (a) potassium ferrocyanideB. (b) nickel carbonylC. (c) potassium ferricyanideD. (d) cobalt (III) hexaammine chloride
Which of the following is the strongest field ligand?A. (a) `CN^-`B. (b) `NO_2^-`C. (c) `NH_3`D. (d) `en`
Among the following , metal carbonyls, the C-O bond is strongest :A. `[Mn(CO)_(6)]^(+)`B. `[Cr(CO)_(6)]`C. `[V(CO)_(6)]^(-)`D. `[Ti(CO)_(6)]^(2-)`
Which of the following is the strongest field ligand?A. (a) `NO_2^(-)`B. (b) `CN^(-)`C. (c) `NH_3`D. (d) `En`
Choose the correct statement regarding complex `CuF_(6)^(-4)`A. Chelation always increase stabilityB. CFSE have strong effect on stabilityC. `Fe("dipy")_(3)^(+3)` is unstableD. All of these
Strongest C-O bond is present inA. `Fe(CO)_(5)`B. `Mn(CO)_(6)^(+)`C. `Cr(CO)_(6)`D. `V(CO)_(6)^(-)`
STATEMENT-1: Coordination isomerism occurs when both the cations and anions are complexes . and STATEMENT-2: Oxidation state of central metal ion in both coordination spheres is always equal.A. Statement-1 is True , Statement-2 is True , Statement-2 is a correct explanation for Statement-1B. Statement-1 is True , Statement-2 is True , Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True , Statement-2 is FalseD. Statement-1 is False , Statement-2 is True

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment