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What is Delta U for the process described by figure. Heat supplied during the process q= 100kJ |
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Answer» `+50kJ` W = area under graph`= (1)/(2) xx 1 xx (1 +2) = (3)/(20 xx 10^(5)N - m^(2)` `Delta U = +100 - (3)/(2) xx (10^(5))/(1000) = 100-150= -50J` |
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