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what is equlibrium constant

Answer» Law of mass action also forms the basis which states that the rate of a chemical reaction is directly proportional to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients. Therefore, given the reaction –\xa0aA(g) + bB(g) ⇔\xa0cC(g) + dD(g)By using the law of mass action here,\xa0\tThe forward reaction rate would be\xa0k+\xa0[A]a[B]b\tThe backward reaction rate would be\xa0k–\xa0[C]c[D]d\xa0where, [A], [B], [C] and [D] being the active masses\xa0and\xa0k+\xa0and\xa0k−\xa0are\xa0rate constants of forward and backward reactions, also the a, b, c, d are the stoichiometric coefficients related to A, B, C and D respectively. However, at the equilibrium – the forward and the backward rates are equal, stating –\xa0Rate of forward reaction = Rate of backward reactionor,\xa0or,\xa0where,\xa0Kc\xa0is the equilibrium constant expressed in terms of the molar concentrations. The equation\xa0Kc\xa0= [ C ]c·[ D ]d\xa0/ [ A ]a·[ B ]b\xa0or, Kc\xa0= Kf\xa0/ Kb\xa0is the Law of Chemical Equilibrium.\xa0The equilibrium constant is therefore related to the standard Gibbs free energy change for the reaction which is stated by the equation –§Gº= -RT ln Keqwhere T states the temperature, R is the universal gas constant and Keq\xa0is the equilibrium constant.


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