1.

What is force on the base of a tank of base area `1.5m^(2)` when it is filled with water upto a height of 1m `(rho_("water")=10^(3)kg//m^(3),P_(0)=10^(5)Pa` and `g=10m//s^(2))`

Answer» Absolute pressure at the bottom of the container is
`P=P_(0)+hrhog=10^(5)+1xx10^(3)xx10=1.1xx10^(5)Pa`
Then force on the base is
`F_("bese")=PA=(1.1xx10^(5))(1.5)=1.65xx10^(5)N`


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