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What is force on the base of a tank of base area `1.5m^(2)` when it is filled with water upto a height of 1m `(rho_("water")=10^(3)kg//m^(3),P_(0)=10^(5)Pa` and `g=10m//s^(2))` |
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Answer» Absolute pressure at the bottom of the container is `P=P_(0)+hrhog=10^(5)+1xx10^(3)xx10=1.1xx10^(5)Pa` Then force on the base is `F_("bese")=PA=(1.1xx10^(5))(1.5)=1.65xx10^(5)N` |
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