What is frequency of first line of Balmer series for H-atom ?

1.	What is frequency of first line of Balmer series for H-atom ?
Answer» `3.29 xx10^(15) s^(-1)` `8.05 xx10^(13) s^(-1)` `8.22 xx10^(15) s^(-1)` `4.57 xx10^(14) s^(-1)` Solution :First lineof balmer series of h atom `therefore` form n=3 to n=2 electron transition `V=(triangleE)/(h)` `=(2.18 xx10^(-18)j)/(6.626xx10^(-34)js)(1)/(3^(2))-(1)/(2^(2))` `=-0.4569 xx10^(15)` `=-4.57 xx10^(14)s^(-1)`

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