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What is `[HS^(-)] & [S^(2-)]` in solution of `0.01M HCl` and `0.1 M H_(2)S` ?(Given that for `H_(2)S,K_(a_(1))=10^(-7)and K_(a_(2))=10^(-14))` |
Answer» `K_(a_(1))=([H^(+)][HS^(-)])/([H_(2)S])rArr 10^(-7)=10^(-7)=(0.01[HS^(-)])/(0.1)rArr [HS^(-)]=10^(-6)M.` `K_(a_(1))xxK_(a_(2))=([H^(+)]^(2)[S^(2-)])/([H_(2)S])` `[S^(2-)]=(10^(-21)xx0.1)/((0.01)^(2))=10^(-18)M` |
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