What is K_(c) for the following equilibrium when the equilibrium concentration of each substance is : [SO_(2)]= 0*60 M, [O_(2)]= 0*82 M and [SO_(3)] = 1*90 M ? 2 SO_(2) (g) + O_(2) (g) hArr 2 SO_(3) (g) K_(c) = [SO_(3)]^(2)/([SO_(2)]^(2) [O_(2)])= (1*90M)^(2)/((0*60 M)^(2) (0*82M)= 12*229 )=12*229 M^(-1) or 12* 229 L mol^(-1)

What is K_(c) for the following equilibrium when the equilibrium conce

1.	What is K_(c) for the following equilibrium when the equilibrium concentration of each substance is : [SO_(2)]= 060 M, [O_(2)]= 082 M and [SO_(3)] = 190 M ? 2 SO_(2) (g) + O_(2) (g) hArr 2 SO_(3) (g) K_(c) = [SO_(3)]^(2)/([SO_(2)]^(2) [O_(2)])= (190M)^(2)/((060 M)^(2) (082M)= 12229 )=12229 M^(-1) or 12* 229 L mol^(-1)
Answer» SOLUTION :` K_(c) = [SO_(3)]^(2)/([SO_(2)] [O_(2)]) = (1.90 M)^(2)/((060 M) ^(2) (0.82M))=12229 M ^(-1) or 12*229 L " mol"^(-1)`