What is K_c for the following equilibrium when the equilibrium concentration of each substance is : [SO_2]=0.60 M, [O_2]= 0.82M and [SO_3] = 1.90 M ? 2SO_(2(g)) + O_(2(g)) hArr 2SO_(3(g))

What is K_c for the following equilibrium when the equilibrium concent

1.	What is K_c for the following equilibrium when the equilibrium concentration of each substance is : [SO_2]=0.60 M, [O_2]= 0.82M and [SO_3] = 1.90 M ? 2SO_(2(g)) + O_(2(g)) hArr 2SO_(3(g))
Answer» Solution :`{:("EQUILIBRIUM reaction:", 2SO_(2(g)) +,O_(2(g)) hArr , 2SO_(3(g))),("Concentration at equili. (M)",0.6, 0.82 , 1.90):}` Equilibrium CONSTANT of reaction is `K_c` , `K_c=[SO_3]^2/([SO_2]^2[O_2])=(1.90M)^2/((0.6M)^2(0.82M))` `= 12.229 M^(-1)` `= 12.229 "L mol"^(-1)`