1.

What is K_(c) for the follwoing reaction in state of equilibrium ? 2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g) Given [SO_2] = 0.6M,[O_2]=0.82 M, and [SO_3] =1.90 M

Answer»

Solution :`2SO_(2)(g) + O_(2)(g) hArr 2SO_(3)(g)`
`K_(c) =([SO_3]^2)/([SO_2]^2[O_2]) = ((1.9 M )XX( 1.9 M))/((0.6 M)xx(0.6 M) xx (0.82 M))`
`= 12.229 M^(-1) =12.229 MOL^(-1)`


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