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What is K_(p) for the equation 2Cl_((g)) hArr Cl_((g)) ? When the system contains equal numberof Cl_((g)) atom and Cl_(2(g)) molecules at 1 bar and 300 k

Answer»


Solution :`2Cl_((g)) harr Cl_(2(g)) implies ""^(N)Cl=""^(n)Cl_(2)` at equilibrium
`X_(Cl)=(1)/(2), PCl=P_("TOTAL")` mole fraction of = `Cl=(1)/(2), ""^(X)Cl_(2)=(1)/(2), PCl_(2)=P_("total")` mole fraction of `Cl_(2)=(1)/(2), PCl_(2) = P_("total") xx Cl_(2)=(1)/(2) :. K_(P)=(PCl_(2))/((PCl)^(2))=((1)/(2))/(((1)/(2))^(2))=2`


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