tion:Hint: We SOLVE this problem by using the formula of simple interest.The formula for the simple interest is given asSI=P×T×R100Where P is the principal amount, T is the time period and R is the rate of interest per annum.After finding the simple interest for all years from 1 to 6 we create a table of ordered pairs containing the number of years as x coordinate and simple interest as y co – ordinate so that we can plot them on a graph of a certain scale.Complete step by step answer:We are given that the principal amount as⇒P=8000We are also given that the rate of interest per annum as⇒R=5Let us assume that the time period as TWe know that the formula for the simple interest is given asSI=P×T×R100Where, P is the principal amount, T is the time period and R is the rate of interest per annum.By using the above formula we get the simple interest in terms of time period as⇒SI=8000×5×T100⇒SI=400TNow, let us take the time period as 1 year then we get the simple interest of 1 year as⇒SI1=400×1⇒SI1=400Now, let us take the time period as 2 years then we get the simple interest for 2 years as⇒SI2=400×2⇒SI2=800Now, let us take the time period as 3 years then we get the simple interest for 3 years as⇒SI3=400×3⇒SI3=1200Now, let us take the time period as 4 years then we get the simple interest for 4 years as⇒SI4=400×4⇒SI4=1600Now, let us take the time period as 5 years then we get the simple interest for 5 years as⇒SI5=400×5⇒SI5=2000Now, let us take the time period as 2 years then we get the simple interest for 2 years as⇒SI6=400×6⇒SI6=2400Now, let us create a table containing the order pairs containing number of years as x co – ordinate and simple interest as y co – ordinate as followsTime period (T)Simple interest (SIi)Ordered pair(T,SIi)1 400 (1,400)2 800 (2,800)3 1200 (3,1200)4 1600 (4,1600)5 2000 (5,2000)6 2400 (6,2400)Now, let us consider a scale of the required graph as followsOn X – axis 1 unit equal to 1 yearOn Y – axis 1 unit equal to RS. 400By using the above scale and the coordinate of points in the table we get the graph asNote: Students may make mistakes in finding the simple interest of 2, 3, 4, …, 6 years.By using the simple interest formula for 2 years we get⇒SI2=8000×5×2100⇒SI2=800But students may make mistakes in taking the principal value for the time period of 2 years.The amount after the 1 year is given as⇒A=8000+400=8400