1.

what is meant by elastic potential energy? Deerive an expression for the elastic potential energy of streched wire. Prove that its elasic energy density is equal to 1/2 x stress x strain

Answer»

Solution :ENERGY Density = `("Energy")/("VOLUME") =((1)/(2) (AY)/(L)x^(2))/(AL)`
`=(1)/(2)((AY x)/(L))(x)/(L)`
`=(1)/(2)(F)/(A)xx(x)/(L) ""[because Y=(FL)/(Ax)]`
`=(1)/(2)"stress" xx"STRAIN"`


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