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What is molarity and normality of a `MnO_(4)^(-)` solution if `32.00 mL` of the solution is required to titrate `40.00mL` of `0.400N Fe^(2+)`? ` MnO_(4)^(-)+5Fe^(2+)+8H^(+)rarrMn^(2+)+5Fe^(3+)+4H_(2)O` |
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Answer» Meq of `MnO_(4)^(-)=Meq.of fe^(2+)` `(Mn^(7+)+5erarrMn^(2+))` `:. Nxx32=40xx0.400` `(Fe^(2+)rarrFe^(3+)+e)` ` N=0.5` or `M_(KMnO_(4))=N_(KMnO_(4))//"valence factor" ` Also, `M_(KMnO_(4))=(0.5)/(5)=0.1M` |
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