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What is molarity and normality of a `MnO_(4)^(-)` solution if `32.00 mL` of the solution is required to titrate `40.00mL` of `0.400N Fe^(2+)`? ` MnO_(4)^(-)+5Fe^(2+)+8H^(+)rarrMn^(2+)+5Fe^(3+)+4H_(2)O`

Answer» Meq of `MnO_(4)^(-)=Meq.of fe^(2+)`
`(Mn^(7+)+5erarrMn^(2+))`
`:. Nxx32=40xx0.400`
`(Fe^(2+)rarrFe^(3+)+e)`
` N=0.5`
or `M_(KMnO_(4))=N_(KMnO_(4))//"valence factor" `
Also, `M_(KMnO_(4))=(0.5)/(5)=0.1M`


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