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What is `((n + 2)! + (n + 1) (n -1)!)/((n +1) (n -1)!)` equal to ?A. 1B. Always an odd integerC. A perfect squareD. None of the above |
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Answer» Correct Answer - C Given expression is : `((n +2) ! + (n +1)!(n -1)!)/((n +1)! (n -1)!) = x` (let) `rArr x = ((n +2) (n +1) n (n -1) ! + (n +1) (n -1)!)/((n +1) (n -1)!)` `= (n +2) n + 1 = n^(2) + 2n + 1 = (n +1)^(2)` Which is a perfect square |
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