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What is N/20 KMnO4 solution |
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Answer» rmality) describes a solution that contains 1 gram equivalent weight (gEW) per litre solution. ... So equivalent wt of KMnO4 in acid medium = MOLECULAR wt/no.of electrons gained in redox reaction = 158/5 =31.6. So for 0.1N KMnO4 solution, you have to dissolve 3.16gKMnO4 in 1L water.Potassium PERMANGANATE 0.1 N: Dissolve 3.3 g of reagent grade potassium permanganate(KmnO4) in 1 L of purified water and heat on a STEAM bath for two hrs. Cover and allow to stand for 24 hrs. Filter through a fine porosity sintered glass crucible, discarding the first 25 mL.Procedure: Dissolve about 3.2 g of KMnO4 in 1 L of deionized water using a LARGE beaker. Cover that beaker with a watch-glass and heat to boiling using a hot plate in the hood. Keep the solution at a gentle boil for about 1 hr. Let the solution stand overnight. |
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