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What is oxidation number of N in HNO_(4) ? |
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Answer» SOLUTION :H + 2 (Peroxide O) + N + 2 (OXYGEN) = 0 `therefore+1+2(-1)+N+2(-2)=0""H-overset(-1)(O)-overset(-1)(O)-UNDERSET(O)underset(||)(N)toO` `thereforeN=+5` |
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