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What is oxidation number of N in HO_(4) ? |
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Answer» Solution :By conventinal method O.N of N is : +1+4(-2)+x=0 or x =+7 this is impossible because N cannot have an O.N of more than + SINCE it has only 5 electrons in valence shell Therefore O.N of N in `HNO_(4)` must be CALCULATED by chemical bonding method the structure of `HNO_(4)`is since it contins a peroxide linkage therefore each of the two oxygen atmos of the peroxide bonds has an O.N of -1 ON of -2 thus if x is the o.n of N then +1-1-1+x-2-2=0 or x=+5 |
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