What is position of element contain n = 3 and electronic configuration is ns^(2)np^(4)in periodic table ?

What is position of element contain n = 3 and electronic configuration

1.	What is position of element contain n = 3 and electronic configuration is ns^(2)np^(4)in periodic table ?
Answer» Solution :`N =3`, third period , `3s^(2)3P^(4)` ` = 10 + ` VALENCE electron ` = 10 + 2 + 4 = 16^(th)` group. Last electron FILLED in p-orbital so it belong in p-block.