1.

What is r.m.s speed of O_(2)molecule if its kinetic energy is 2 k cal "mol"^(-1)?

Answer»

`7.24 xx 10^`2 m/sec 
`3.5 xx 10^2` m/sec 
`1.8 xx 10^1` m/sec 
`3.5 x 10^1` m/sec 

Solution :`KE = 3/2 PV implies underset(RMS)(C ) = sqrt((3PV)/(M)) = sqrt((2KE)/M)`
`sqrt((2 xx 2 xx 10^3 xx 4.18)/(32 xx 10^(-3)) = 7.24 xx 10^(2)` sec.


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