What is the acceleration of a body moving on a circular path of radius

1.	What is the acceleration of a body moving on a circular path of radius 400 m. If it has 1. constant speed of 40 ms-1 2. speed increases at 3 ms-2
Answer» A body on a circular path has two kinds of accelerations: radial & linear 1. If speed is constant linear acceleration is zero & radical acceleration is ar = \(\frac {v^2}{r}\) v = 40ms^-2 r = 400 m ⇒ ar = \(\frac {40 \times 40}{400}\) = 4ms^-2 2. If the speed increases at 3 m/s², it has a linear acceleration of 3ms^-2. a = \(\sqrt {a_r^2+a_1^2}\) = \(\sqrt {3^2+4^2}\) = 5 ms^-2.

What is the acceleration of a body moving on a circular path of radius 400 m. If it has 1. constant speed of 40 ms-1 2. speed increases at 3 ms-2

Answer»

A body on a circular path has two kinds of accelerations: radial & linear

1. If speed is constant linear acceleration is zero & radical acceleration is ar = \(\frac {v^2}{r}\)

v = 40ms^-2

r = 400 m

⇒ ar = \(\frac {40 \times 40}{400}\) = 4ms^-2

2. If the speed increases at 3 m/s², it has a linear acceleration of 3ms^-2.

a = \(\sqrt {a_r^2+a_1^2}\)

= \(\sqrt {3^2+4^2}\)

= 5 ms^-2.