1.

What is the action of ammonia on the following : (a) Br_(2) (b) I_(2)(c) Na (d) Cu^(2+) (e ) CoCl_(2) ?

Answer»

Solution :(a) `NH_(3)`, with `Br_(2)`, forms `NH_(4)Br` and `N_(2)`
`8NH_(3) + 3Br _(2) to 6NH_(4)Br + N_(2)`
(b) Ammonia with `I_(2)` forms brown PRECIPITATE of nitrogen triodide ammonia, `NH_(3)NI_(3)`
`2NH_(3) + 3I_(2) to NH_(3) NI_(2) +3HI`
`NH_(3) NI_(2)` is explosive in dry state and decomposes to produce `N_(2)` and `I_(2)`
`8NH_(3)NI_(3) to 5N_(2) + 9I_(2) + 6NH_(4)I`
(c) Ammonia with electropositive metal like Na and K forms amide.
`2Na +2NH_(3) to underset("deep BLUE COMPLEX")([Cu(NH_(3))_(4)]_((aq)))`
(d) `Cu_((aq))^(2+) + 4NH_(3)^((aq)) to underset("deep blue complex")([Cu(NH_(3))_(4)]_((aq)))`
(e) `CoCl_(2) + 6NH_(3) to [Co(NH_(3))_(6)]Cl_(2)`


Discussion

No Comment Found