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What is the amount of substance give the volume of 3.0 dm3

Answer» NE =P×dV=3.0×(5.0−3.0)=6.0litre−atm=6.0×101.3J=607.8JLet ΔT be the CHANGE in temperatureHeat ABSORBED =m×s×ΔT=10.0×18×4.184×ΔTGiven, P×dV=m×s×ΔTor ΔT= m×sP×dV = 10.0×18.0×4.184607.8 =0.807Final temperature=290+0.807=290.807K


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