What is the amount of work done when 0.5 mol of methane, CH_(4)(g) is subjected to combustion at 300K? (given, R = 8.314 JK^(-1)mol^(-1)):

What is the amount of work done when 0.5 mol of methane, CH_(4)(g) is

1.	What is the amount of work done when 0.5 mol of methane, CH_(4)(g) is subjected to combustion at 300K? (given, R = 8.314 JK^(-1)mol^(-1)):
Answer» `-2494` J `-4988` J `+4988` J `+2494` J Solution :`CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(L)` Work done,`W = -p DeltaV = -Deltan_(g) RT` `Deltan_(g)= 1 -3 = -2, T = 300K` `w = -(-2 xx 8.314 xx 300)` = 4988.4 J For 0.5 mol of `CH_(4)` ` w = (4988.4)/(2) = 2494.2`