1.

What is the amount of work done when 0.5 mole off methane, CH_(4)(g), is subjected to combustion at 300 K? (Given, R=8.314JK^(-1)mol^(-1))

Answer»

`-2494J`
`-4988J`
`+4988J`
`+2494J`

Solution :COMBUSTION of methane
`CH_(4)+2O_(2)(G)toCO_(2)(g)+2H_(2)O(g)`
`W=-pxxDeltaV=-nRT`
`=-(-0.5)xx8.314xx300=+2494J`


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