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What is the amount of work done when 0.5 mole off methane, CH_(4)(g), is subjected to combustion at 300 K? (Given, R=8.314JK^(-1)mol^(-1)) |
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Answer» `-2494J` `CH_(4)+2O_(2)(G)toCO_(2)(g)+2H_(2)O(g)` `W=-pxxDeltaV=-nRT` `=-(-0.5)xx8.314xx300=+2494J` |
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