What is the amount of work done when two moles of an ideal gas is comoressed from a volume of 1 m^(3) to 10 dm^(3) at 300 K against a pressure of 100 kPa?

What is the amount of work done when two moles of an ideal gas is como

1.	What is the amount of work done when two moles of an ideal gas is comoressed from a volume of 1 m^(3) to 10 dm^(3) at 300 K against a pressure of 100 kPa?
Answer» 99 KJ `-99` kJ `114.9` kJ `-114.9` kJ Solution :`w = p_(ext)(V_(2)-V_(1))` `p_(ext = 100 KP = 10^(5)Pa` `therefore w = 10^(5)Pa(1 - 0.001)m^(3)` ` = 10^(5) xx 99.9 xx 10^(-2) Pam^(3)` ` = 99.9 xx 10^(3)J (because Pa m^(3) = J)` = 99.9 kJ