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What is the angular momentum of an electron in (i) 2 s orbital (ii) 4f orbital ? |
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Answer» SOLUTION :Angular momentum of ELECTRON in any orbital `= SQRT(l(l + 1)) = (h)/(2pi)` `:.` For 2 s orbital, `l = 0, " " :.` angular momentum `= sqrt(0(0 + 1)) (h)/(2pi) = 0` For 4f orbital, `l = 3, " " :.` angular momentum `= sqrt(3(3 +1)) (h)/(2pi) = 2 SQRT3 (h)/(2pi) = sqrt3 (h)/(pi)` |
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